Difference between revisions of "Tech Support Flow Chart Assignment"
From WLCS
| Line 22: | Line 22: | ||
if choice == "y": | if choice == "y": | ||
print "You ate without me?" | print "You ate without me?" | ||
| − | + | if choice == "n": | |
choice2 = input("Would you like to get some Five Guys? (y/n)") | choice2 = input("Would you like to get some Five Guys? (y/n)") | ||
if choice2 == "y": | if choice2 == "y": | ||
print "YES! Five Guys rocks!" | print "YES! Five Guys rocks!" | ||
| − | + | if choice2 == "n": | |
print "WHAT?!? You are crazy! Five Guys rocks!" | print "WHAT?!? You are crazy! Five Guys rocks!" | ||
</source> | </source> | ||
Revision as of 13:20, 21 September 2012
Objective: Create a program that asks the user various questions that leads them through the File:TechSupportChart.jpg
Competencies:
- 043 Design a program using an algorithm, pseudocode, and/or a flowchart.
- 044 Code the program, using a programming language.
- 045 Execute the program with sample data.
- 046 Debug the program.
Procedures:
- Create a python script named techSupport.py
- Ask the user the first question: "Do you have someone in mind? (y/n)"
- Store the user's input into a variable
- If the variable is a "y", then proceed to ask them "Are they available? (y/n)"
- If the variable is a "n", then proceed to "GPF"
- HINT: You will have NESTED if statements as you proceed through the geek dating chart.
Example:
choice = input("Have you eaten yet today? (y/n)")
if choice == "y":
print "You ate without me?"
if choice == "n":
choice2 = input("Would you like to get some Five Guys? (y/n)")
if choice2 == "y":
print "YES! Five Guys rocks!"
if choice2 == "n":
print "WHAT?!? You are crazy! Five Guys rocks!"
